In this paper is concerned with a machine proof to the following geometric inequality, which was presented by . Zirakzadeh in 1964: given any triangle and three points which divide the perimeter of into three equal parts, the perimeter of is equal to or greater than the one half of that of . By representing the Zirakzadeh inequality as radical problem of form , where are cubic polynomials of and belongs to a polyhedron in with 14 vertices, 21 edges and 9 faces, we first construct a cube and a polynomial of total degree 8 so that and in , then we prove two lemmas on error analysis for testing the positive definiteness of a continuous differentiable function on a rectangular region or a polytope through its values at the vertices, and finally we show the inequality for by partitioning the polyhedron into a finitely many small rectangular sets which edges are or larger and the values of at the vertices of the rectangular sets exceed the test numbers for positive definiteness. The total computation time for the third step is 159.124 hours on personal computers. %(on an IBM Thinkpad T61 machine with one Intel Duo 2 CPU and an IBM workstation with two Intel Xeon CPUs). We also establish a mechanical method for computing the lower and upper bounds of polynomials and the test numbers of radical expressions over polyhedra in .
ZENG Zhenbing
, ZHANG Jingzhong. , {{custom_author.name_en}}.
A Mechanical Proof to a Geometric Inequality of Zirakzadeh Through Rectangular Partition of Polyhedra. Journal of Systems Science and Mathematical Sciences, 2010, 30(11): 1430-1458 https://doi.org/10.12341/jssms09280